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Thanks!

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- Thread starter nothing123
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- #1

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Thanks!

- #2

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f(g(x))' = f'(g(x))g'(x)

Now replace f with v, g with x, x with t,the first ' with d/dt, the second ' with d/dx (since f is a function of g aka x), and the third ' with d/dt and voila you have

dv/dt = (dv/dx)(dx/dt)

- #3

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If v is a function of x only, and x is a function of t only, then if you increase t by a small amount ∆t, then x increases by a small amount ∆x = (dx/dt)∆t. (1)

But v also increases, by a small amount ∆v = (dv/dx)∆x. (2)

So, combining (1) and (2):

∆v = (dv/dx)∆x = (dv/dx)(dx/dt)∆t.

- #4

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Great, thanks for your help guys.

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