Designing an Ultrasonic Range Finder with a PIC Microcontroller

  • Thread starter Thread starter counterstruck
  • Start date Start date
  • Tags Tags
    Radar Ultrasonic
Click For Summary
The discussion focuses on designing an ultrasonic range finder using a PIC microcontroller to generate a 0-5V 40KHz pulse. The user seeks to boost the signal to achieve a -9V to 9V swing for greater power transmission and distance. Paralleling hex inverters is suggested to increase current drive into the piezo element, resulting in an 18Vpp differential signal. Additionally, safety considerations for medium-power ultrasound transmissions near humans are highlighted, emphasizing the importance of understanding safe power levels and duty cycles. Overall, the conversation underscores the technical challenges and safety aspects of ultrasonic range finder design.
counterstruck
Messages
1
Reaction score
0
Hi

I am designing a ultrasonic range finder. I am part of design group with the challenge of building a robot that can find its way through a known course.

I found some circuits avaliable on the net. There is a section on the transmitter circuitry that confuses me. I am using microcontroller to generate a 0 - 5V 40KHz burst of pulses. I want to boost the signal to have a larger voltage swing, and current drive to achieve larger power transmission hence further distance. I can amplify the voltage to 0 - 9V, but now how do I achieve a -9V to 9V swing?

The circuit uses hex inverters. Doesn't a hex inverter represent a logic 0 as ground? The explanation given about why two hex inverters are in parallel is still not clear to me.

I am using a PIC microcontroller, which drives out about 20mA. I want to achieve the max power transmission for a 40KHz piezo transducer. For current amplification, how does one design a current amplify for a -9V to 9V signal?
 

Attachments

  • inverters.JPG
    inverters.JPG
    25.2 KB · Views: 534
Engineering news on Phys.org
Thread moved to EE forum. Welcome to the PF, counterstruck.

The paralleling of the inverters is meant to boost the current driven into the piezo element. With two inverters in parallel, you get about twice the drive current. There will be slight mismatches in timing for the two parallel gates, but if they are in the same IC package, the mismatch shouldn't make much difference.

Since each side of the piezo is being driven with a 9Vpp signal, and since the two signals are out of phase, that results in a 2x9Vpp = 18Vpp differential signal being driven across the piezo element.

BTW, can you tell us a little about safety considerations for medium-power ultrasound transmissions near humans? What power levels and duty cycles are considered "safe"? That should be a part of your research and report and construction -- making sure that you are building something that is safe to operate around unprotected humans. (Or at least understanding what precautions and protections you should use if you need to use higher power levels in your ultrasound ranging devices.)
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 29 ·
Replies
29
Views
5K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
7K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 32 ·
2
Replies
32
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K