Destructive electromagnetic waves

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SUMMARY

The discussion centers on the interaction of two photons that are 180 degrees out of phase when they encounter a surface. It is established that such a scenario does not produce a resultant electromagnetic wave capable of exerting tension on the surface. The conversation emphasizes that photons, as quantum particles, do not possess a classical phase and that their wave functions interact in complex ways, leading to probabilities of interaction with surfaces rather than deterministic outcomes.

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  • Basic grasp of Feynman diagrams and quantum field theory
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Taqa
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Ive been wondering about this for about two days and i have a simple question and that is , if I have two photons that are 180 degrees out of phase, passing through a surface perpendicular to the photons velocity vector then will the EM fields exert tension on the surface?(in this case the material of the surface is not made up by any other constituent particles)
 
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If they are exactly 180 degrees out of phase, there is no electromagnetic wave that could do anything.
Taqa said:
(in this case the material of the surface is not made up by any other constituent particles)
This does not exist.
 
Taqa said:
if I have two photons that are 180 degrees out of phase
It doesn't work like that; we're dealing with quantum particles and you can't apply classical notions to them. A photon doesn't have "a phase" because it isn't like a little squiggle - as shown on the Feynman (peace be upon him), in his diagrams. The wave functions, associated with each of the sources of the two photons will combine to make it very unlikely that there will be a photon interaction with 'the screen' or detector at a minimum (calculated in a classical way) and very likely that there will be an interaction at a calculated maximum (or one of the maxima on either side of the central maximum).
 

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