Determine if a function is continuous

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    Continuous Function
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Discussion Overview

The discussion centers around the continuity of a piecewise function at the point x = -2. Participants are analyzing the limit of the function as x approaches -2 and its value at that point to determine continuity.

Discussion Character

  • Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant presents the piecewise function and asks whether it is continuous at x = -2.
  • Another participant states that to ensure continuity, the limit as x approaches -2 must equal the function's value at that point, which they propose should be 4.
  • A different participant calculates the limit and claims to have found it to be -4, suggesting that it does not equal 4.
  • A subsequent reply agrees with the calculation of -4 and concludes that this indicates the function is not continuous at x = -2.

Areas of Agreement / Disagreement

There is disagreement regarding the limit of the function as x approaches -2, with one participant asserting it is -4, while another suggests it should be 4. The discussion remains unresolved regarding the continuity of the function.

Contextual Notes

Participants have not explicitly defined the conditions under which the limit is evaluated, and there may be assumptions about the behavior of the function near x = -2 that are not fully explored.

kendalgenevieve
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$$f(x)=\begin{cases}\dfrac{x^2-4}{x+2}, & x\ne-2 \\[3pt] 4, & x=-2 \\ \end{cases}$$

Determine if its continuous at x=-2
 
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To ensure continuity, we require:

$$\lim_{x\to-2}\frac{x^2-4}{x+2}=4$$

Is this true?
 
MarkFL said:
To ensure continuity, we require:

$$\lim_{x\to-2}\frac{x^2-4}{x+2}=4$$

Is this true?

I just got -4 so no it does not equal 4
 
Hi kendalgenevieve! Welcome to MHB! ;)

kendalgenevieve said:
I just got -4 so no it does not equal 4

Good!
That means it's not continuous.
 

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