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## Homework Statement

A particle is in a box with length L. A spring attached to the particle is fixed at x=0. How can we determine the potential due to the spring is weak?

## Homework Equations

H=p

^{2}/2m

Si(x)=sqrt(2/L)sin(npix/L)

E

_{n}=n

^{2}pi

^{2}hbar

^{2}/2mL

^{2}

V(x)=kx

^{2}

## The Attempt at a Solution

If I base my answer solely off of the quadratic equation, than that something must be x. If x is very small next to k, than wouldn't V(x) be small? I'm not sure if this is correct, however since there was so much information given in the problem... Help me please?

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