The disk rolls without slipping on the horizontal surface, and at the instant represented, the center O has the velocity vO = 2.2 m/s and acceleration aO = 5.5 m/s2 with directions shown in the figure. For this instant, the particle A has the indicated speed u = 3.2 m/s and time rate of change of speed = 6.6 m/s2, both relative to the disk with directions shown in the figure. Determine the absolute velocity vA and acceleration aA of particle A.
I have attached an image of the question
VA = VO + wXr + Vrel
The Attempt at a Solution
I'm honestly confused as to how to start this question. I'm not given the angular velocity so initially I tried to solve for it.
v = wXr
I know that the velocity at point O is -2.2i but how should I determine r? Or should I use the velocity at A instead?
Any help would be appreciated.
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