Determine the fraction of the volume

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SUMMARY

The discussion focuses on calculating the volume occupied by an ideal gas and the fraction of that volume occupied by gas molecules. Using the Ideal Gas Law (PV=nRT), the volume for 1.25 mol of gas at 310K and 101kPa is determined to be 31882.43 m³. Additionally, the volume of a gas molecule approximated as a sphere with a diameter of 2.5x10^-10 m is calculated to be 8.18x10^-30 m³. The fraction of the total volume occupied by the molecules can be derived without knowing the number of molecules, demonstrating that the fraction is independent of sample size.

PREREQUISITES
  • Understanding of the Ideal Gas Law (PV=nRT)
  • Basic knowledge of molecular volume calculations
  • Familiarity with unit conversions (e.g., kPa to Pa)
  • Concept of molecular dimensions and their implications in volume calculations
NEXT STEPS
  • Explore advanced applications of the Ideal Gas Law in real-world scenarios
  • Learn about the kinetic molecular theory and its relation to gas behavior
  • Investigate the implications of molecular size on gas properties
  • Study the concept of molar volume and its significance in chemistry
USEFUL FOR

This discussion is beneficial for chemistry students, educators, and anyone interested in understanding gas behavior and molecular volume calculations in the context of ideal gases.

olso4142
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[SOLVED] Ideal Gases

Homework Statement


A gas has a temperature of 310K and a pressure of 101kPa (a.) find the volume occupied by 1.25 mol of this gas, assuming its ideal. (b.) assuming the gas molecules can be approximated as a small sphere of diameter 2.5x10^-10, determine the fraction of the volume found in part (a) that is occupied by the molecules.


Homework Equations


PV=nRT



The Attempt at a Solution


(a.) V=nRT/P
V= (1.25mol)(8.31J/mol*K)(310K)/0.101Pa
V= 31882.43 m^3

(b.)d= 2.5x10^-10
V(sphere)= 8.18x10^-30

n=PV/RT
n= (.101Pa)(31882.43m^3)/(8.31J/mol K)(310K)
n= 1.25 mol *6.022x10^23= 7.5275x10^23 molecules

do i just multiple these together and then find the fraction from the first volume?
 
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Yes, that works fine.

but notice, Vsphere/V can be determined without ever knowing n.

Since this fraction should not depend on how large your sample is, the number should "cancel out." solve for this fraction using variables (without plugging in numbers) and you will see n go away.
 
For the first part...1kPa=1x10^3[/tex]Pa <br /> and for the fraction occupied, vol.occupied by gas/vol.of sphere
 

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