Determine the magnitude of the current in the circuit

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SUMMARY

The discussion focuses on calculating the current and voltage in a circuit using Ohm's Law. The current (I) is determined to be 0.3846A by applying the formula I = (30V - 10V) / (27Ω + 5Ω + 8Ω + 12Ω). The voltage between points A and B (Vab) is calculated as +19.6158V, indicating that point B is at a higher potential than point A.

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dedra73
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This is a problem I had for homework. I want to make sure I did it correctly.

http://i90.photobucket.com/albums/k256/dedra73/circuit-2.jpg

circuit-2.jpg



(a) Determine the magnitude of the current in the circuit and
I = (30-10)V / (27+5+8+12)Ω
=20V/52Ω
=.3846A

(b) The magnitude of the voltage between the points labeled A and B.
Vab = 30V - .3846A * 27Ω
= 30V- 10.3842V
= +19.6158V

(c) State which point, A or B, is at the higher potential.
Point B is 19.6158V higher than A
 
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Looks good to me!
 

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