Determine the number of solutions for a homogeneous system

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SUMMARY

To determine the number of solutions for a homogeneous system represented by Ax = 0, where A is an m*n matrix and x is an n*1 vector, one must first assess the rank of matrix A. By applying the rank-nullity theorem, the nullity, which is the dimension of the kernel of A, is calculated as n - m', where m' is the rank of A. The number of independent solutions is 1 if n - m' ≤ 0, and n - m' if it is greater than 0.

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Hi all,

I would like to know how to determine the number of solutions for a Homogeneous system.
Ax = 0

A is a m*n matrix and x is a n*1 vector.

There are m equations and n unknowns. I'd like to know how to determine the number of solutions to this system.

Thank you in advance.
 
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First, thinking of the m rows as vectors, determine how many of them are independent (the "rank" of A). Call that number m'. By the "rank-nullity" theorem, the nullity, the dimension of kernal(A), will be n- m'. The number of (independent) solutions will be 1 if n- m'\le 0, and n- m' if it is greater than 0.
 
Thanks a lot for the answer...
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

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