Determine the tension in each wire?

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SUMMARY

The problem involves determining the tension in two wires supporting a 100kg sign, with angles of 35˚ and 55˚ to the roof. The weight of the sign is calculated using the formula Fg = mg, resulting in a force of 981 N. To find the tensions T1 and T2 in the wires, one must resolve these tensions into their horizontal and vertical components, ensuring that the sum of the forces in both directions equals zero, as the sign is in equilibrium.

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Homework Statement


A 100kg sign is suspended by two wires with angles of 35˚ and 55˚ (to the roof) and meet at a 90˚ angle at the sign. Determine the tension in each wire.
(I'm not sure if I described very well. It was on a diagram)


Homework Equations


Fg=mg
aˆ2+bˆ2=cˆ2
cˆ2=aˆ2+bˆ2−2ab cos C
thats all i know for sure

The Attempt at a Solution


Fg=mg
=(100)(9.81)
=98.1 N

I also drew a tail-to-tip diagram.
But i am stuck.
 
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Try splitting each tension (call them T1 and T2) into components. The sign should be in equilibrium, so the sum of the horizontal forces should be zero as well as the sum of the vertical forces.

That will give you two equations which you can then solve for T1 and T2.
 
Concentrate on the point where the two wires attach to the sign. What are the forces acting there? Hint: it isn't just the weight of the sign.
 

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