Determine the torque of a driver if driven is known

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The discussion focuses on calculating the input torque required for a driver wheel with a diameter of 6 meters and an expected RPM of 4, given a driven side torque of 3300 Nm. Utilizing two angle drives with gear ratios of 40:1 and 10:1, the output RPM reaches 1600 RPM. The calculation indicates that the driver torque must be 400 times the driven torque, resulting in a theoretical torque of 1,320,000 Nm. However, this figure does not account for friction losses in the gearing, suggesting that the actual driving torque will be higher than this theoretical value.

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I have a driver wheel at 6 meters diameter, expected Rpm=4, Torque=?,

Using two angle drives, at ratios of 40:1 and 10:1 inline (in>4rpm x 40=160rpm>out) & (in>160rpm x 10=1600rpm @3,300nm) driven side,

Can somebody please help to determine the required input torque on the the driver side
 
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If the rpm goes up by a factor of 400 due to gearing, the torque must decrease by a factor of 400. Therefore if you somehow measure 3300 nm at the driven end, the torque of the driver is 400*3300 nm. However, this assumes there are no friction losses in the gearing. The driving torque will be greater than 1320000 nm due to the losses.
 
Well that puts my nose out of per-portion, thank you for your reply
 

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