1. A bullet of mass 0.0020 kg and traveling at 300 m/s strikes the center of a 3.0 kg block of wood which is sitting on a fence post. The block of wood is 2.0 m above the ground. I got the velocity using the eq (m1v1 + m2v2)/Mtotal = 0.2 m/s [correct if incorrect please] I then got the horizontal distance by finding time and using x = v*t Determine the velocity at which the bullet-block system hits the ground. Be sure to include an angle. 2. a^2 + b^2 = c^2 Vfinal = at + Vinitial Xfinal = 1/2at (m1v1 + m2v2) / Mtotal 3. I figured this would involve a right triangle, so I tried solving for the length of the sides. I believe this is where I went wrong. The height of the triangle is 6.272 because i used Vfinal=at+Vinitial, 9.8(.64)+0. I then used the Pythagorean theorem but the answer seemed strange. Thanks.