Velocity of a 1-kg block after it has dropped 0.54 m

[volcore]

Faster than what?

Bad wording on my part, since kinetic energy is defined as 1/2 mv^2, wouldn't the 3.5kg block receive more of the system's kinetic energy since it has more mass, and both are moving at the same velocity?

 

[PeroK]

Bad wording on my part, since kinetic energy is defined as 1/2 mv^2, wouldn't the 3.5kg block receive more of the system's kinetic energy since it has more mass, and both are moving at the same velocity?

Yes, exactly.

 

[volcore]

Yes, exactly.

So where do I go from there?

Would this be right:
(2.5kg)g(0.54m) = 1/2 m1v1^2 + 1/2m2v2^2
1.35g = 3.75v1^2 + 0.5v2^2?

 

[PeroK]

So where do I go from there?

Would this be right:
(2.5kg)g(0.54m) = 1/2 m1v1^2 + 1/2m2v2^2
1.35g = 3.75v1^2 + 0.5v2^2?

What do you know about the relationship between $v_1$ and $v_2$?

Note that you should keep the units in these equations.