Determine Total Work done by the Force

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SUMMARY

The total work done by a force F = 10 N acting on a collar moving from position A to position B along a curved track, with a constant angle θ = 35° to the positive x-axis, is calculated to be 8.60 J. The user initially attempted to compute work done in the x and y directions separately, yielding 1.433 J and 0.574 J respectively. However, the correct approach requires considering the vertical component's sign, which affects the total work calculation. The final consensus indicates that the total work done is indeed 8.60 J.

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Northbysouth
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Homework Statement


The collar moves on a curved track from position A to position B, and slides with neglible friction. A force F = 10 N acts upon the collar from position A to position B, and the direction of the force is always oriented θ = 35° with a positive x-axis as shown. Determine the total work done by the force F on the collar from position A to position B.


Homework Equations





The Attempt at a Solution



I tried finding the work done by the forces in the x and y directions.

In the x direction there's:

0.175*10cos(35) = 1.433 J

0.1*10sin(35) = 0.574 J

I then tried taking the magnitude of this, but the answer should be 8.60 J, which i obviously won't get.

Any suggestions would be greatly appreciated.
 

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Northbysouth said:

Homework Statement


The collar moves on a curved track from position A to position B, and slides with neglible friction. A force F = 10 N acts upon the collar from position A to position B, and the direction of the force is always oriented θ = 35° with a positive x-axis as shown. Determine the total work done by the force F on the collar from position A to position B.


Homework Equations





The Attempt at a Solution



I tried finding the work done by the forces in the x and y directions.

In the x direction there's:

0.175*10cos(35) = 1.433 J

0.1*10sin(35) = 0.574 J

I then tried taking the magnitude of this, but the answer should be 8.60 J, which i obviously won't get.

Any suggestions would be greatly appreciated.

What you have done is basically correct but what about the sign of of the work done in the vertical direction ? I think the answer would be 0.86 J.
 

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