Determine voltage from a conductor in magnetic field

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SUMMARY

The discussion focuses on determining the induced electromotive force (EMF) in a wire moving perpendicular to a constant magnetic field. The relationship between the Lorentz force, expressed as F = q v ∧ B, and the induced potential difference is established through the equation emf = l v ∧ B, which can be manipulated to yield emf = dΦ/dt, where Φ represents magnetic flux. The conversation highlights the connection between Faraday's law and motional EMF, emphasizing that induced EMF occurs whether the wire moves or the magnetic field changes.

PREREQUISITES
  • Understanding of Faraday's law of electromagnetic induction
  • Familiarity with the Lorentz force equation
  • Knowledge of magnetic flux and its calculation
  • Basic principles of electromotive force (EMF)
NEXT STEPS
  • Study the derivation of Faraday's law in detail
  • Learn about the applications of the Lorentz force in electromagnetic systems
  • Explore the concept of magnetic flux and its role in circuit analysis
  • Investigate the effects of varying magnetic fields on induced EMF
USEFUL FOR

Physics students, electrical engineers, and educators seeking to deepen their understanding of electromagnetic induction and its practical applications in circuits and devices.

BBruyne
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Hi,

I would like to know how to get the potential difference due to a constant local magnetic field acting on a wire moving at a constant speed perpendicular to the field. What is the link between F = q v ∧ B and the actual difference of potential in the circuit ? How to determine the induced electric field ? I have attached an image to illustrate it.

Thank you,

Bbruyne
 

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Thanks for the link, very nice website. I am learning Faraday's law and I am trying to link motional emf to his law. I do understand that a squared loop of wire of length l moving with a velocity v into a stationnary magnetic field B will experience a Lorentz force and this force will induce an emf. From emf = l v∧B, with a bit of manipulation, we arrive to emf = dΦ/dt. http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elevol.html#c3That means that if the loop of wire is not moving but we approach a magnet into the loop, we get an induced emf. How can we justify this with the initial idea emf = l v∧B. We could say that the loop is moving relatively to the magnet but, it is moving in a parallel direction to the magnetic field of the magnet, thus v∧B = 0.
 

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