MHB Determine whether the following SERIES converge or diverge

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The discussion focuses on determining the convergence or divergence of two series. The first series, $$\sum^{\infty}_{n=1} \frac{n^3}{3^n}$$, converges absolutely using the ratio test, with a limit L of 1/3, which is less than 1. The second series, $$\sum^{\infty}_{n=1} \frac{n}{n^2 + 1}$$, diverges according to the limit comparison test; however, the explanation lacks detail on the series used for comparison. Participants emphasize the importance of providing a complete explanation for the limit comparison test to clarify the reasoning behind the divergence. Overall, clear and thorough justification is essential for determining series behavior.
shamieh
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can someone check my answers

Determine whether the following series converge or diverge. You may use any appropriate test provided you explain your answer.

4.$$\sum^{\infty}_{n=1} \frac{n^3}{3^n}$$

A: So for this one i used the ratio test and found that L = 1/3 which is < 1 therefore the series converges absolutely

5. $$\sum^{\infty}_{n = 1} \frac{n}{n^2 + 1}$$

A: diverges by limit comparison test
 
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shamieh said:
4.$$\sum^{\infty}_{n=1} \frac{n^3}{3^n}$$

A: So for this one i used the ratio test and found that L = 1/3 which is < 1 therefore the series converges absolutely
Correct. (There is no need to add "absolutely" here since all terms are positive.)

shamieh said:
5. $$\sum^{\infty}_{n = 1} \frac{n}{n^2 + 1}$$

A: diverges by limit comparison test
The problem statement asked to explain your answer. Mentioning the limit comparison test but not saying with what series you compare the given one is not a sufficient explanation. It would be nice to also say how you know that the second series converges or diverges.
 

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