Determine which functions are rational

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SUMMARY

The discussion centers on identifying rational functions based on their definitions. It concludes that only functions (i) and (iii) qualify as rational functions, as they can be expressed as fractions of polynomials. Functions (ii) and (iv) do not meet this criterion, as attempts to convert them into polynomial fractions fail, particularly due to the non-polynomial nature of their denominators. The analysis emphasizes the importance of polynomial forms in determining rationality.

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  • Understanding of rational functions and their definitions
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chwala
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Homework Statement
consider the attached problem
Relevant Equations
rational functions
1628756836435.png


Ok in my thinking, i would say that it depends on ##x##, if ##x## belongs to the integer class, then the rational functions would be ##i ## and ##iii##...but from my reading of rational functions, i came up with this finding:

1628757186237.png


I would appreciate your input on this.
 
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Well according to the above definition only (i) and (iii) are rational functions.

(ii) or (iv) doesn't look like they are a fraction of polynomials neither I can find a way to transform them to a fraction of two polynomials. For example if we multiply both the numerator and denominator of (iv) by ##\sqrt{x-1}## we get $$\frac{x-1}{\sqrt{x^2-1}}$$ the numerator has become polynomial, but the denominator still isn't polynomial.
 
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Delta2 said:
Well according to the above definition only (i) and (iii) are rational functions.

(ii) or (iv) doesn't look like they are a fraction of polynomials neither I can find a way to transform them to a fraction of two polynomials. For example if we multiply both the numerator and denominator of (iv) by ##\sqrt{x-1}## we get $$\frac{x-1}{\sqrt{x^2-1}}$$ the numerator has become polynomial, but the denominator still isn't polynomial.
thanks, i guess i missed the term "polynomial" cheers mate:cool:
 
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