Determing frequency shift of an ultrasound

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SUMMARY

The discussion focuses on calculating the frequency shift of ultrasound reflected from blood moving in an artery using a Doppler blood flow unit emitting at 5.0 MHz. The initial calculation yielded a frequency shift of approximately 666 Hz, but this was deemed incorrect. The correct approach involves using the Doppler effect equations, specifically adjusting for the movement of the blood corpuscles as both the source and receiver of the ultrasound waves. The final equation for the frequency at the receiver is f(receiver) = f(transmitted) * (Vs - Vb) / (Vs + Vb).

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Homework Statement


A Doppler blood flow unit emits ultrasound at 5.0 MHz.

What is the frequency shift of the ultrasound reflected from blood moving in an artery at a speed of 0.20 m/s?

Express your answer using two significant figures.

Homework Equations


f' = f0(v/v-Vs)
frequency shift = f' - f0

f0 = 5*10^6 Hz
v = 1500 m/s (assumed)
Vs = 0.20 m/s

The Attempt at a Solution


Plugging in the numbers we get the following equation for frequency shift:

(5*10^6)*[1500/(1500-0.2)]-5*10^6

Which comes out to approx 666 Hz. or 6.7 *10^2 Hz using 2 significant figures. However, this problem comes from an online homework set and according to that 6.7 *10^2 is not the correct solution.

Does anyone have an idea of what I am doing wrong? Thanks in advance for any and all help!
 
Last edited:
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Hi grigri9, welcome to PF.
We have here a case of the "listener" (the blood corpuscles) moving away from a stationary source, and thus the frequency, f corpuscle that will be reflected by the corpuscles will be
f corpuscle = f(transmitted)[(Vs - Vb)/Vs

For the reflected waves, reflection, the corpuscles are the source and the "listener" is the receiver. The frequency at the receiver will be
f(receiver) = f(corpuscles)*Vs/(Vs + Vb)

from which we get
f(receiver) = f(transmitted)*(Vs-Vb)/(Vs+Vb)
 

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