.Determining Convergence/Divergence of 100n/2^n with Ratio Test

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SUMMARY

The discussion focuses on using the Ratio Test to determine the convergence or divergence of the series defined by the term 100n/2^n. The key formula applied is p = lim┬(n→∞)[a_(n+1)/a_n], where p < 1 indicates convergence, p > 1 indicates divergence, and p = 1 means the test is inconclusive. Participants worked through the limit expression lim┬(n→∞)[(100(n+1)/2^(n+1))(2^n/100n)] to simplify and evaluate the limit, ultimately leading to a conclusion about the series' behavior.

PREREQUISITES
  • Understanding of the Ratio Test in series convergence
  • Familiarity with limits in calculus
  • Basic algebraic manipulation skills
  • Knowledge of exponential functions and their properties
NEXT STEPS
  • Study the application of the Ratio Test in more complex series
  • Learn about other convergence tests such as the Root Test and Comparison Test
  • Explore the concept of limits in greater depth, particularly L'Hôpital's Rule
  • Investigate the behavior of exponential functions in series
USEFUL FOR

Students studying calculus, particularly those focusing on series convergence, as well as educators looking for examples of the Ratio Test application.

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Homework Statement



Use the ratio test to determine convergence or divergence of 100n/2^n

Homework Equations



p= lim┬(n→∞)[a_(n+1)/a_n]

p<1 ,convergent
p>1 ,divergent
p=1 ,ratio test fails

The Attempt at a Solution



I'm not even sure if I'm doing this right, but i get:

lim┬(n→∞)[(100_(n+1)/2^(n+1))(2^n/100n)]

and I don't know how to proceed from there
 
Physics news on Phys.org
\lim_{n-&gt;inf} |\frac{100(n+1)}{2^{n+1}}*\frac{2^n}{100n}|

You can cancel stuff, then evaluate the limit.
 

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