Is the Interval of Convergence for (x-2)^n / n^(3n) from -1 to 5?

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SUMMARY

The interval of convergence for the series \((x-2)^n / n^{3n}\) is determined to be from -1 to 5 using the ratio test. The endpoints require further analysis, revealing that the series diverges at \(x = 5\) and converges at \(x = -1\) due to the alternating series test. The series \(\sum (-1)^n/n\) converges conditionally, while \(\sum 1/n\) diverges. Understanding the distinction between conditional and absolute convergence is crucial for accurate endpoint evaluation.

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  • Understanding of the Ratio Test for series convergence
  • Knowledge of the Alternating Series Test
  • Familiarity with concepts of conditional and absolute convergence
  • Basic calculus, particularly series and sequences
NEXT STEPS
  • Study the Alternating Series Test in detail
  • Learn about conditional vs. absolute convergence
  • Explore examples of series that converge conditionally
  • Review the Ratio Test and its applications in series analysis
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Students studying calculus, particularly those focusing on series convergence, as well as educators teaching convergence tests and series analysis.

isukatphysics69
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Homework Statement


interval of convergence for
n=1 to inf
(x-2)n / n3n

Homework Equations

The Attempt at a Solution


i used the ratio test and solved for x and got that the interval of convergence is from -1 to 5. now i have to test the endpoints to determine which ones will make the series either converge or diverge. it looks to me that they both will diverge but on the multiple choice homework i do not see a choice for both diverging although i do see a choice for the -1 converging and the 5 diverging. now the 5 endpoint makes sense to me for divergence because it will be 1/n which is a divergent harmonic series
but the -1 converging is not making sense

(-3)n / n3n
(-1)1 / n
divergent

what am i not understanding here?
 
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isukatphysics69 said:

Homework Statement


interval of convergence for
n=1 to inf
(x-2)n / n3n

Homework Equations

The Attempt at a Solution


i used the ratio test and solved for x and got that the interval of convergence is from -1 to 5. now i have to test the endpoints to determine which ones will make the series either converge or diverge. it looks to me that they both will diverge but on the multiple choice homework i do not see a choice for both diverging although i do see a choice for the -1 converging and the 5 diverging. now the 5 endpoint makes sense to me for divergence because it will be 1/n which is a divergent harmonic series
but the -1 converging is not making sense

(-3)n / n3n
(-1)1 / n
divergent

what am i not understanding here?

You are not understand that the series ##\sum 1/n## diverges but the series ##\sum (-1)^n/n## converges. (Recall the "alternating series" test.)

In fact, the second sum is well-known: ##\sum_{n=1}^{\infty} (-1)^n/n = - \ln 2.##
 
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You don’t understand the difference between conditional and absolute convergence.
 
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