MHB Determining if a sequence is arithmetic

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The sequence defined by An = 2 + 6n produces the first five terms: 2, 8, 14, 20, and 26. To determine if it is an arithmetic sequence, the difference between successive terms must be constant. The calculation shows that a(n+1) - a(n) equals 6, confirming that the difference is indeed constant. Therefore, the sequence is classified as an arithmetic sequence. The conclusion is that the sequence meets the criteria for being arithmetic due to the consistent difference of 6.
fluffertoes
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Question:

Find the first 5 terms of this series and determine if it is an arithmetic sequence.

An= 2 + 6n

Help please!
 
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Re: Sequences and series help ASAP please!

fluffertoes said:
Question:

Find the first 5 terms of this series and determine if it is an arithmetic sequence.

An= 2 + 6n

Help please!

If we have an AP, then we must have:

$$a_{n+1}-a_{n}=C$$ where C is some constant...is this what we have?
 
Re: Sequences and series help ASAP please!

MarkFL said:
If we have an AP, then we must have:

$$a_{n+1}-a_{n}=C$$ where C is some constant...is this what we have?

All the info i was given is what I put in the original question up there, yikes
 
Re: Sequences and series help ASAP please!

fluffertoes said:
All the info i was given is what I put in the original question up there, yikes

We are given:

$$a_{n}=2+6n$$

Therefore:

$$a_{n+1}=2+6(n+1)$$

So, what is the difference:

$$a_{n+1}-a_{n}$$ ?
 
Re: Sequences and series help ASAP please!

MarkFL said:
We are given:

$$a_{n}=2+6n$$

Therefore:

$$a_{n+1}=2+6(n+1)$$

So, what is the difference:

$$a_{n+1}-a_{n}$$ ?

1? I'm not sure
 
Re: Sequences and series help ASAP please!

fluffertoes said:
1? I'm not sure

Let's work it out...

$$a_{n+1}-a_{n}=\left(2+6(n+1)\right)-\left(2+6n\right)=\left(2+6n+6)\right)-\left(2+6n\right)=(2+6n)+6-(2+6n)=6$$

This tells us that any two successive terms in the given sequence differ by 6, which is a constant, and therefore we do have an arithmetic sequence. :)
 

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