Determining if an operator is degenerate

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Discussion Overview

The discussion revolves around determining whether a given operator is degenerate, particularly in the context of differential operators. Participants explore the relationship between degeneracy and symmetries, as well as methods for formally identifying degeneracy in various operators.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant suggests using the equation det(Q-##\lambda##)=0 to determine degeneracy, questioning how to apply this to differential operators.
  • Another participant explains that degeneracy often arises from symmetries, specifically noting that the operator ##\frac{d^2}{dx^2}## is translation invariant, leading to a set of degenerate states represented by displaced sine functions.
  • A follow-up inquiry asks for formal methods to determine degeneracy beyond identifying symmetries.
  • One participant mentions advanced group theory methods for systematically finding symmetries of differential operators and notes the existence of "accidental" degeneracies that may not be easily identified.
  • A participant provides a differential equation formulation for the operator, indicating that solutions can include sine and cosine functions, but emphasizes that solving differential equations is not always straightforward.

Areas of Agreement / Disagreement

Participants generally agree that degeneracy is related to symmetries, but there is no consensus on a formal method to determine degeneracy for all operators. The discussion remains open regarding the identification of degeneracies beyond symmetry considerations.

Contextual Notes

Limitations include the complexity of identifying accidental degeneracies and the challenges associated with solving differential equations, which may not yield straightforward solutions.

Physgeek64
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Hi,

I was wondering how you can formally determine whether a given operator is degenerate. I undertand you can produce the 'usual equation' det(Q-##\lambda ##)=0 and solve for ##\lambda ##, where Q is our operator. But if Q is a differential (for example ##\frac{p^2}{2m}= - \bar{h} \frac{d^2}{dx^2}## ) how can one write such an equation.

p.s. I only used this example as I know that the operator is degenerate with sin and cos of the same argument. Other examples are welcome :)

Many thanks in advance!

Also- don't know why I can't get my equations to format properly? ^^
< Moderator's note: fixed. You had a ( instead of { >
 
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Degeneracy of an operator's eigenvalue spectrum is usually a result of some symmetry. In your example the operator ##\frac{d^2}{dx^2}## is translation invariant which means that the set of all displaced sine functions of same wavelength, ##sin(a x + b)##, is a set of mutually degenerate states (a is kept constant and b can have any real value).
 
Last edited:
hilbert2 said:
Degeneracy of an operator's eigenvalue spectrum is usually a result of some symmetry. In your example the operator ##\frac{d^2}{dx^2}## is translation invariant which means that the set of all displaced sine functions of same wavelength, ##sin(a x + b)##, is a set of mutually degenerate states.

Ahh okay that makes sense in this case. In general, do you know how this can be formally determined for any given operator (other than looking for a symmetry)?

Thanks :)
 
^ There are probably some methods to systematically find all the symmetries of a differential operator, but that's quite advanced group theory. There are also so called "accidental" degeneracies that aren't caused by symmetries, but there's probably no efficient way to find them if they exist.
 
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Physgeek64 said:
if Q is a differential (for example ##\frac{p^2}{2m}= - \bar{h} \frac{d^2}{dx^2}## ) how can one write such an equation.

As a differential equation. For example, in your case we would have, for a function ##f(x)##,

$$
- \hbar^2 \frac{d^2}{dx^2} f(x) - \lambda f(x) = 0
$$

which obviously has solutions for ##f(x)## that are sines and cosines. This still doesn't guarantee finding a solution, since solving differential equations is not a completely mechanical process. But that's how you would start.
 

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