Determining Moles: H2O2 Decomposition

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Discussion Overview

The discussion revolves around the decomposition of hydrogen peroxide (H2O2) and the calculation of moles and grams of products formed, specifically focusing on the amount of oxygen produced from a given mass of H2O2. It also touches on a related question about the conversion of moles between lead nitrate and aluminum nitrate.

Discussion Character

  • Homework-related, Mathematical reasoning

Main Points Raised

  • One participant presents the decomposition reaction of H2O2 and asks how many grams of oxygen are produced from 15.0 grams of H2O2.
  • Another participant inquires about the conversion of moles from lead nitrate to aluminum nitrate, expressing difficulty with mole calculations.
  • A third participant seeks clarification or assistance regarding the first question about H2O2 decomposition.
  • A later reply reiterates the decomposition reaction and encourages the original poster to determine moles as a starting point for solving the problem, suggesting that practice would be beneficial.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the specific calculations or methods to solve the problems presented, indicating that multiple viewpoints and uncertainties exist regarding the calculations of moles and grams.

Contextual Notes

The discussion lacks detailed assumptions or specific methods for calculating moles and grams, and the mathematical steps necessary for resolving the questions remain unresolved.

stealthinstinct
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2H2O2---> 2H2O+O2

In the decomposition equation above, how many grams of oxygen is made when 15.0 grams of H2O2 decomposes?
 
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6 moles of lead nitrate would create how many moles of aluminum nitrate?

I also need help with this.. i suck at moles...
 
anyone know?
 
stealthinstinct said:
2H2O2---> 2H2O+O2

In the decomposition equation above, how many grams of oxygen is made when 15.0 grams of H2O2 decomposes?

You might start by determining moles. Since you say you suck at it, the practice will do you good. Show us your practice...
 

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