Determining non-conserved work from a collision

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The discussion focuses on calculating non-conserved work during a collision, emphasizing that kinetic energy is not conserved due to momentum transfer. The initial kinetic energy is noted as 94.556, with potential energy being zero. Participants clarify that during a collision, kinetic energy can be lost, and the final velocity, calculated using conservation of momentum, is 3.075. This final velocity allows for the determination of changes in kinetic energy and work done. It is suggested that solving the problem algebraically before substituting values can simplify the process.
JoeyBob
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Homework Statement
see attached
Relevant Equations
W=change in kinetic energy
So I know from a previous part of the problem that the kinetic energy right before the collision is 94.556.

The non conserved work would also equal the change in kinetic energy + change in potential energy.

What I don't understand is how the potential or kinetic energy would change during the collision. The potential energy is already 0 and wouldn't the kinetic energy just be transferred (so the object would slow down because its heavier).

answer is suppose to be -47.32
 

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JoeyBob said:
wouldnt the kinetic energy just be transferred
Never assume work is conserved without good reason. In a coalescence, as here, you can use conservation of momentum to find the new speed, and you will see that KE has been lost.
 
haruspex said:
Never assume work is conserved without good reason. In a coalescence, as here, you can use conservation of momentum to find the new speed, and you will see that KE has been lost.
So from conservation of momentum I find that the final velocity was 3.075, which gives a final kinetic energy, which allows me to calculate the change, which let's me find the work.
 
JoeyBob said:
So from conservation of momentum I find that the final velocity was 3.075, which gives a final kinetic energy, which allows me to calculate the change, which let's me find the work.
Yes, but it is much better, for several reasons, to solve a problem purely algebraically, only plugging in numbers at the very end. Had you done that, you would have found it was unnecessary to find the velocities, neither before impact nor after.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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