Determining OH- and pH of a weak base

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SUMMARY

The discussion focuses on calculating the hydroxide ion concentration ([OH-]) and pH of a 0.210 M bicarbonate (HCO3-) solution. The user attempted to apply the Kb value of 1.7 x 10^-9 for bicarbonate in the equilibrium equation but encountered an error in their calculations. The correct approach requires considering both the dissociation and hydrolysis of bicarbonate, as it is an amphiprotic substance. The user is directed to a resource for detailed pH calculations involving amphiprotic salts.

PREREQUISITES
  • Understanding of acid-base equilibria
  • Familiarity with the concept of amphiprotic substances
  • Knowledge of Kb and Ka values
  • Ability to solve quadratic equations
NEXT STEPS
  • Review the concept of amphiprotic substances and their behavior in solution
  • Learn how to apply the Kb and Ka values in equilibrium calculations
  • Study the method for calculating pH from hydroxide ion concentration
  • Explore the use of equilibrium expressions in weak base solutions
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Chemistry students, educators, and professionals involved in acid-base chemistry, particularly those working with weak bases and amphiprotic substances.

dnt
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the question is simply to determine the [OH-] and pH of a solution that is .210 M in HCO3-

first of all if i can get [OH-] then i can easily get pH by converting [OH-] to [H+] and then doing the -log[H+] so that part is easy. i just cannot get [OH-]

what i did was first write the equation:

HCO3- + H20 --> H2CO3 + OH-

and use the Kb value for HCO3- which I looked up to be 1.7 x 10^-9

then used .21-x for the concentration of HCO3- and x to be the concentrations of both H2CO3 and OH-

then using the Kb equation I got:

x^2 / (.21-x) = 1.7 x 10^-9

solving for x = 1.9 x 10^-5

shouldnt that be [OH-]? but its not correct. can someone show me what mistake i made? thanks.
 
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