- #1

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^{2}= (4 * pi

^{2}* a

^{3})/(G(M+m)) to find the orbital period of Earth where:

P = orbital period

a = semi-major axis = 1.50e11 m

G = 6.67e-11 m

^{3}kg

^{-1}s

^{-2}

M = mass of sun (in this case) = 1.989e30 kg

m = mass of Earth = 5.972e24 kg

I have been trying to find the orbital period of the Earth but the answers I've been getting make no sense.

P

^{2}= (4 * pi

^{2}* (1.50e11)

^{3}) / (G(1.989e30 + 5.972e24))

P = 31690989.27

What are the units on P? I tried following the units as they cancelled each other and I ended up with s kg

^{-2}. Any advice would be helpful.

Thanks!

- Marcin