Determining resistances in circuits

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SUMMARY

This discussion focuses on determining resistances in circuits, specifically involving a variable resistor Y and a fixed resistor X valued at 1 Megaohm. The maximum output voltage Vo is established as 15V when the circuit reaches saturation. The relationship between the resistors is defined using the voltage divider formula, where Vo is derived from the equation Vo = 11Vy/(Rx + Ry). The output voltage at saturation is confirmed to be equal to the power supply voltage of 15V, emphasizing the importance of understanding op-amp behavior in this context.

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  • Understanding of op-amp circuits and their ideal behavior
  • Familiarity with voltage divider principles
  • Knowledge of resistor values and their impact on circuit performance
  • Ability to manipulate algebraic equations in circuit analysis
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  • Investigate the implications of saturation in op-amp circuits
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Electrical engineering students, circuit designers, and anyone involved in analyzing or designing op-amp based circuits will benefit from this discussion.

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Homework Statement



Refer to the attachment for the diagram

(1) If the value of the variable resistor Y is varied, what is the maximum value of the output voltage Vo?

(2) If the resistance value of resistor X is 1 Megaohm, what is the resistance of the variable resistor Y immediately after saturation has occurred?

Homework Equations





The Attempt at a Solution



(1) I think is 12V but i am not sure how to reason it out.

(2) At saturation, Vo=15V so 15=11Vy

Vy=(Ry)/(Rx+Ry)

I know how to carry on from here.

The answer took Vo as 12V so isn't that at saturation the output is the greater or equal to the power supply which is 15 V in this case?
 

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You can either re-derive the function of the amplifier or just look up the non-inverting amplifier.

1) You are looking for a function; that is, unless R1 and R2, or a relationship between the two, are given. You have the right formula for voltage divider, just figure out when that voltage divider, which is the input voltage to the op-amp is at a maximum.

2) The output voltage is now 15V, that's correct. Use the fact that an op-amp draws no current (ideally, though with these resistances you'd get behavior quite different from an ideal op amp). Again, without knowing R1 and R2 you will have to find the algebraic solution, which I stopped at because it looked tedious and nasty.
 

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