Determining the concentration of ions in ppm

  • Context: Chemistry 
  • Thread starter Thread starter rwooduk
  • Start date Start date
  • Tags Tags
    Concentration Ions
Click For Summary
SUMMARY

The discussion centers on the determination of calcium ion concentration in a solution containing calcium chloride and sodium carbonate. The paper referenced, "Calcium carbonate scale formation in pipes," states that the solutions are equimolar but does not clarify that the 3500 ppm of Ca2+ corresponds to a molarity of 0.0875M. Participants clarify that the ppm is calculated based on the mass of calcium chloride required for the solution, and the confusion arises from the implication that sodium carbonate contains calcium ions, which it does not. The final concentration of Ca2+ in the mixed solution is suggested to be a dynamic steady-state value.

PREREQUISITES
  • Understanding of molarity and ppm calculations
  • Knowledge of precipitation reactions in chemistry
  • Familiarity with calcium chloride and sodium carbonate properties
  • Basic comprehension of dynamic steady-state concepts in chemical solutions
NEXT STEPS
  • Research the calculation methods for converting molarity to ppm
  • Study precipitation reactions involving calcium carbonate
  • Explore dynamic steady-state conditions in chemical systems
  • Examine the effects of flow rates and temperature on ion concentrations in solutions
USEFUL FOR

Chemists, chemical engineers, and students studying solution chemistry, particularly those interested in ion concentration calculations and precipitation reactions.

rwooduk
Messages
757
Reaction score
59
Homework Statement
It's in a paper I am reading (not homework)
Relevant Equations
ppm = (mass of solute ÷ mass of solution x 1,000,000
I'm a little confused by a basic statement in a paper I am reading. It says that calcium chloride (1 M) and sodium carbonate (1 M) i.e. equimolar, have "a predetermined concentration of 3500 ppm of Ca2+"...

Untitled.png


I understand that the mixing of these two will cause a precipitation reaction, but don't understand how the ppm of calcium ions was determined, was it measured / calculated somehow? Why would there be Ca2+ in the sodium carbonate solution? The statement seems a little confusing.

Thank you in advance for any help understanding this.

EDIT paper is Calcium carbonate scale formation in pipes: effect of flow rates, temperature, and malic acid as additives on the mass and morphology of the scale
 
Physics news on Phys.org
It says they are equimolar; that is the molar concentrations of sodium carbonate and calcium chloride are equal to each other; they are not necessarily equal to 1M. 3500ppm Ca2+ is 0.0875M. There is no Ca in the sodium carbonate solution - there can't be; the statement must mean that the (equal) molar concentration was chosen to give 3500ppm Ca2+ in the calcium chloride solution. It is a little awkwardly expressed, I agree.
 
  • Like
Likes   Reactions: rwooduk
mjc123 said:
It says they are equimolar; that is the molar concentrations of sodium carbonate and calcium chloride are equal to each other; they are not necessarily equal to 1M. 3500ppm Ca2+ is 0.0875M. There is no Ca in the sodium carbonate solution - there can't be; the statement must mean that the (equal) molar concentration was chosen to give 3500ppm Ca2+ in the calcium chloride solution. It is a little awkwardly expressed, I agree.

Thank you mjc. So, then I guess that the ppm was calculated by using the mass of calcium chloride required to give 1 M solution divided by the mass of solution, would that be correct?

Also, it says...

Untitled.png


So, that would be equimolar right?
 
rwooduk said:
So, then I guess that the ppm was calculated by using the mass of calcium chloride required to give 1 M solution divided by the mass of solution, would that be correct?
No. First, it is ppm of calcium, not calcium chloride. Second, I have already told you that 3500 ppm Ca corresponds to a molarity of 0.0875M, not 1M.
rwooduk said:
So, that would be equimolar right?
Yes. You didn't tell us this before. Is there any more information you're hiding? It's not clear to me now what's going on, or what the 3500ppm refers to. It can't be the stock solutions if they are 1M. Are the stock solutions diluted before being mixed? Your quote suggests not. Is 3500ppm the concentration of Ca2+ after mixing the solutions? I wouldn't have thought so; CaCO3 is not that soluble. I'm really confused now.
 
Reference, please.
 
  • Like
Likes   Reactions: jim mcnamara
Apologies for the confusion and thank you for the further help with this. The paper is Calcium carbonate scale formation in pipes: effect of flow rates, temperature, and malic acid as additives on the mass and morphology of the scale

The excerpts from the paper which I uploaded as images are from Section 2.1.

https://www.sciencedirect.com/science/article/pii/S1876619614000102
 
Hmmm. It's still not quite clear. It looks like 3500 ppm is the concentration of Ca2+ in the mixed solution. The initial concentration would be 0.5M (20,000 ppm), and I would expect the concentration after complete precipitation to be lower than 3500, but this is a flow system, and deposition is slow, so maybe 3500 ppm is a dynamic steady-state value. They could have been clearer. (For example, the wording literally implies that the sodium carbonate solution was made from calcium chloride crystals!)
 
  • Like
Likes   Reactions: rwooduk
mjc123 said:
Hmmm. It's still not quite clear. It looks like 3500 ppm is the concentration of Ca2+ in the mixed solution. The initial concentration would be 0.5M (20,000 ppm), and I would expect the concentration after complete precipitation to be lower than 3500, but this is a flow system, and deposition is slow, so maybe 3500 ppm is a dynamic steady-state value. They could have been clearer. (For example, the wording literally implies that the sodium carbonate solution was made from calcium chloride crystals!)

Thanks mjc for taking the time to read the section of the paper. Yes, I was quite confused by their description. Your interpretation has been a great help. Thank you.
 
Actually, the paper merely states that the test solution was prepared from a stock 1M solution to a final concentration of 3500 ppm Ca+2. That would mean that the test solution would be at 7000 ppm Ca+2 and the CO3-2 solution would be at whatever ppm CO3-2 would be equimolar with that.
 
  • Like
Likes   Reactions: rwooduk

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
16K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 1 ·
Replies
1
Views
8K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
7K
Replies
43
Views
19K
Replies
1
Views
4K