Determining the focal length of a compound lens

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SUMMARY

The discussion centers on determining the focal length of a compound lens system composed of two biconvex lenses, L_1 and L_2, with focal lengths of 15 cm and 25 cm, respectively. The correct formula to use is 1/f_c = 1/f_1 + 1/f_2, leading to a calculated focal length of +9.375 cm for the compound lens. The confusion arose from the treatment of focal lengths versus radii of curvature, clarifying that both biconvex lenses have positive focal lengths.

PREREQUISITES
  • Understanding of lens types, specifically biconvex lenses
  • Familiarity with the lens maker's equation
  • Basic knowledge of optics and focal lengths
  • Ability to perform calculations involving fractions and reciprocals
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  • Explore the effects of combining different types of lenses
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Homework Statement


A biconvex lens, L_1, with focal length of magnitude \left|<br /> f_1 <br /> \right|<br /> = 15 cm is used with a second biconvex lens, L_2, with focal length of magnitude \left|<br /> f_2 <br /> \right|<br /> = 25 cm to form a compound lens system.

If the two lenses are placed in mutual contact what is the focal length of the compound lens?

Homework Equations



\frac{1}{f_c} = \frac{1}{f_1} + \frac{1}{f_2}

The Attempt at a Solution


It's just a matter of plugging into the above equation.. However do I use the the absolute values or the fact that for a biconvex lens

<br /> f_1 &gt; 0

and

<br /> f_2 &lt; 0?

Solution given is +9.375 cm, which suggests you use the absolute values, however I am not fully convinced as it was not specified in the course notes whether to use absolute values or not.

Not using absolute values, I find the focal length to be +37.5 cm
 
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Sorry, I figured it out... both are biconvex lenses therefore their focal lengths are positive. I believe I got confused with radius' of curvatures.. the solution given is the correct one.
 
For a biconvex lens:

R1 > 0 and R2 < 0 (Radius of curvature)

not the focal lengths... :confused:
 

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