Determining the possible time interval between two sine waves

Click For Summary

Homework Help Overview

The discussion revolves around determining the time interval between two identical sinusoidal waves that travel in the same direction but start at different times. The problem involves concepts of wavelength, wave speed, phase difference, and frequency.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between phase difference and time interval, exploring how to derive the time interval from the phase difference. Questions arise regarding the meaning of the phase difference and its implications for the time interval calculation.

Discussion Status

Participants are actively engaging with the problem, attempting to clarify the connection between phase difference and time interval. Some guidance has been provided regarding the use of frequency and the relationship between phase and time, but no consensus has been reached on the specific calculations.

Contextual Notes

There is a focus on understanding the implications of different phase shifts and how they relate to the time interval. The problem constraints include the specific values for wavelength and wave speed, which are integral to the discussion.

randoreds
Messages
24
Reaction score
0
ok I just got stuck half way into a problem, I would like it if someone explained it!

Ok the question says, two identical sinusodial waves with a wavelength of 3.0 m and traveling in the same direction with a v of 2m/s. Starting from the same point, just the second waves starts later. and the amplitude of the resultant wave is the same as each of the initial waves.

Find the min. time interval between the two waves

So, I would suppose I would need the phase difference, so I found it and it is 2/3 pi. now I asked my teacher and he said to use this equation to find the time interval.

T/3 = 1/3f

so I get I would just sub for f with v and wavelength

what I don't get is the 3. I see it comes from my phase difference, but could someone explain that a little further. Like what if my phase shift was 4/5 pi? would the equation become T/5 =1/5f ?

because I don't really get where the two goes and how I would know to put a 3 under T
 
Last edited:
Physics news on Phys.org
I see emptiness...
 
rollingstein said:
I see emptiness...

Fixed it!
 
randoreds said:
So, I would suppose I would need the phase difference, so I found it and it is 2/3 pi. now I asked my teacher and he said to use this equation to find the time interval.

T/3 = 1/3f

so I get I would just sub for f with v and wavelength

what I don't get is the 3. I see it comes from my phase difference, but could someone explain that a little further.
That (2/3)[/size] being radians?

You know that 1 cycle corresponds to 2[/size] radians.
So then x cycles correspond to (2/3)[/size]. Find x.
 
randoreds said:
T/3 = 1/3f
Yes, period = 1/frequency, and you can calculate the frequency from wavelength and speed. What remains is to say what one whole period corresponds to in terms of phase, and what fraction of that is the phase shift you found.
 
haruspex said:
Yes, period = 1/frequency, and you can calculate the frequency from wavelength and speed. What remains is to say what one whole period corresponds to in terms of phase, and what fraction of that is the phase shift you found.
T

Thanks, I think I get it. just to be sure. Theoretically if I found the phase shift to be 3/5 pi and all the other variable were the same as in the problem. My T would be 2/5 T because one sine wave is 2/5 pi ahead of the other, right?
 
randoreds said:
if I found the phase shift to be 3/5 pi and all the other variable were the same as in the problem. My T would be 2/5 T because one sine wave is 2/5 pi ahead of the other, right?
No. Try answering my question first: what, in radians, would a phase shift of a whole period be? Then, what fraction of that would 3/5 pi be?
 

Similar threads

  • · Replies 30 ·
2
Replies
30
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
20
Views
5K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K