Determining whether the non-integral form of Gauss' law applies

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SUMMARY

The discussion centers on the application of Gauss' law, specifically the conditions under which the non-integral form can be utilized. Gauss' law states that the net electric flux through a closed surface equals the enclosed charge divided by the permittivity of free space, expressed as $$\int_S {\bf{E} \cdot d \bf{A}} = \frac{Q}{\epsilon_0}$$. The simplified form, $$\sum{} EA = \frac{Q}{\epsilon_0}$$, is valid when the electric field is constant across the surface area being considered and when the perpendicular component of the electric field to the area is also constant. This understanding is crucial for correctly applying Gauss' law in various scenarios.

PREREQUISITES
  • Understanding of Gauss' law and its mathematical formulation
  • Familiarity with electric flux and its calculation
  • Knowledge of electric fields and their properties
  • Basic calculus, particularly integration techniques
NEXT STEPS
  • Study the derivation and applications of Gauss' law in electrostatics
  • Explore the concept of electric flux in different geometries, such as spheres and cylinders
  • Learn about the conditions for applying the non-integral form of Gauss' law
  • Investigate the implications of non-uniform electric fields on flux calculations
USEFUL FOR

Students of physics, particularly those focusing on electromagnetism, educators teaching Gauss' law, and professionals in fields requiring a solid understanding of electric fields and their applications.

etotheipi
I've just been learning about Gauss' law which as far as I can tell states that the net electric flux through a surface equals the enclosed charge divided by the permittivity of free space, and is often expressed as the integral $$\int_S {\bf{E} \cdot d \bf{A}} = \frac{Q}{\epsilon_0}$$In some cases I've read it's fine to take the electric field out of the integral to obtain something like the following $$\sum{} EA = \frac{Q}{\epsilon_0}$$ where instead we can just add up the flux emanating from all of the relevant surfaces on a simple shape. An example would be adding the two contributions to flux at both ends of a cylinder through an infinite charged sheet.My question is under what circumstances is this a "legal" move? It can't just be when we have a uniform electric field, since we can also apply this simplified version of Gauss' law to a spherical surface around point charge whose radius can be chosen to be whatever you want (i.e. E \cdot 4 \pi r^{2} = \frac{Q}{\epsilon_0})

I came to the conclusion that this is only valid when the electric field is constant at all points on each area being considered, which made sense to me since then E would be constant with respect to the surface area elements in the integral and we can consequently take it out. Is this sort of the right way of thinking about it? Thanks
 
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etotheipi said:
I came to the conclusion that this is only valid when the electric field is constant at all points on each area being considered, which made sense to me since then E would be constant with respect to the surface area elements in the integral and we can consequently take it out. Is this sort of the right way of thinking about it?

And also importantly add the additional stipulation that the perpendicular component of E to that area is constant.
 
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