- #1

Leo Liu

- 353

- 156

Gauss' law: $$\iint_{\partial A}\vec E\cdot d\vec A=\frac{Q}{\epsilon_0}$$

Suppose we have a unevenly charged non-conducting spherical shell, in which a Gaussian surface is placed. In this case, is the electrical field on A 0, given that there is no charge inside A? I came up with this example to ascertain whether the G's law applied to a body with nonuniform charge distribution.

Thanks.

EDIT: In hindsight, I realized I asked a very dumb question. Sorry for wasting the time of all of us. Haha.

Suppose we have a unevenly charged non-conducting spherical shell, in which a Gaussian surface is placed. In this case, is the electrical field on A 0, given that there is no charge inside A? I came up with this example to ascertain whether the G's law applied to a body with nonuniform charge distribution.

Thanks.

EDIT: In hindsight, I realized I asked a very dumb question. Sorry for wasting the time of all of us. Haha.

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