Diagonalizing a matrix using perturbation theory.

In summary, the conversation discusses the use of perturbation theory to diagonalize a given matrix. The method involves finding the eigenvalues and eigenvectors of the unperturbed Hamiltonian, represented by the matrix given in the conversation. The calculation of perturbations can be done using <Psi|H'|Psi>, but the necessary wavefunction is not provided in the given information. Instead, the conversation suggests using the eigenstates of the unperturbed Hamiltonian, denoted as |1>, |2>, and |3>. The given matrix is the representation of the unperturbed Hamiltonian in this basis, which can be used to calculate the corrections and ultimately diagonalize the matrix H.
  • #1
PsychoDash
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Homework Statement



Consider the following Hamiltonian.

H=[itex]\begin{pmatrix} 20 & 1 & 0 \\1 & 20 & 2 \\0 & 2 & 30 \end{pmatrix}
[/itex]
Diagonalize this matrix using perturbation theory. Obtain eigenvectors (to first order) and eigenvalues (to second order).

Ho=[itex]\begin{pmatrix} 20 & 0 & 0 \\0 & 20 & 0 \\0 & 0 & 30 \end{pmatrix}
[/itex]
H'=[itex]\begin{pmatrix} 0 & 1 & 0 \\1 & 0 & 2 \\0 & 2 & 0 \end{pmatrix}
[/itex]

Homework Equations


The Attempt at a Solution



In general, diagonalizing a matrix involves finding its eigenvalues and then writing the eigenvalues on the diagonal with zeros elsewhere. Despite that, I'm just not sure how to approach this question.
 
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  • #2
How do you calculate corrections in perturbation theory? What equations do you have? Do you have degenerate states?

It's really just a matter of figuring out which formulas you need to use and plugging everything in. You can get the needed matrix elements by inspection.
 
  • #3
That's what's throwing me off. There is no "physical system" as I have come to understand it. All I'm given is what I wrote above. I understand that to calculate perturbations in general, you use <Psi|H'|Psi>, but that gets me back to needing a wavefunction to operate on. All I have is this set of matrices.
 
  • #4
You don't need a wave function for the system. You need the eigenstates of the unperturbed Hamiltonian. Let's call those [itex]\vert 1 \rangle[/itex], [itex]\vert 2 \rangle[/itex], and [itex]\vert 3 \rangle[/itex]. The matrix you've been given is the representation of [itex]\hat{H}[/itex] relative to that basis. In other words,
[tex]\begin{pmatrix}
\langle 1 \lvert \hat{H} \rvert 1 \rangle & \langle 1 \lvert \hat{H} \rvert 2 \rangle & \langle 1 \lvert \hat{H} \rvert 3 \rangle \\
\langle 2 \lvert \hat{H} \rvert 1 \rangle & \langle 2 \lvert \hat{H} \rvert 2 \rangle & \langle 2 \lvert \hat{H} \rvert 3 \rangle \\
\langle 3 \lvert \hat{H} \rvert 1 \rangle & \langle 3 \lvert \hat{H} \rvert 2 \rangle & \langle 3 \lvert \hat{H} \rvert 3 \rangle
\end{pmatrix} = \begin{pmatrix} 20 & 1 & 0 \\1 & 20 & 2 \\0 & 2 & 30 \end{pmatrix}
[/tex]
Does that clear things up?
 
  • #5
How does that help diagonalize H?
 

What is diagonalization of a matrix?

Diagonalization of a matrix is a process of finding a similar matrix that has only diagonal elements. This is done by finding a set of linearly independent eigenvectors and arranging them in a matrix, which is then multiplied with the original matrix and its inverse to get a diagonal matrix.

What is perturbation theory?

Perturbation theory is a mathematical method used to approximate solutions to problems that cannot be solved exactly. It involves breaking down a complex problem into simpler ones and then using small changes or perturbations to find an approximate solution.

How does perturbation theory help in diagonalizing a matrix?

Perturbation theory can be used to find an approximate solution to the eigenvectors and eigenvalues of a matrix, which are needed for diagonalization. By introducing small perturbations to the original matrix, we can iteratively improve the approximation and eventually obtain a more accurate diagonal matrix.

What are the benefits of using perturbation theory for diagonalization?

Using perturbation theory allows us to find an approximate solution to diagonalizing a matrix without having to solve the problem exactly, which can be time-consuming for large matrices. It also provides a way to improve the accuracy of the solution by iteratively refining the perturbations.

Are there any limitations to perturbation theory in diagonalizing a matrix?

Yes, perturbation theory may not always provide an accurate solution for diagonalization, especially when the perturbations are too large or the matrix is ill-conditioned. In some cases, it may also be difficult to determine the appropriate perturbations to use. Additionally, perturbation theory may not work for non-linear or non-Hermitian matrices.

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