- #1

Jaco Viljoen

- 160

- 9

**Mod note**: Moved from technical math section, so no template.

The diameter of a circle has endpoints P(0,0) and Q(8,-4) Find the equation:

First I will find the midpoint:

[tex]M(x,y)=(x1+x2)/2,(y1+y2)/2[/tex]

[tex]=8/2,-4/2)[/tex]

[tex]M(x,y)=(-4,-2)[/tex]

Then I will find the radius:

[tex]r^2=(x-h)^2+(y-k)^2[/tex]

[tex]r^2=(0-4)^2+(0+2)^2[/tex]

[tex]r^2=16+4[/tex]

[tex]r^2=20[/tex]

so

[tex](x-4)^2+(y+2)^2=20[/tex]

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