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Diameter of a circle endpoints P(0,0) Q(8,-4) what equation:

  1. Jun 4, 2015 #1
    Mod note: Moved from technical math section, so no template.
    The diameter of a circle has endpoints P(0,0) and Q(8,-4) Find the equation:

    First I will find the midpoint:
    [tex]M(x,y)=(x1+x2)/2,(y1+y2)/2[/tex]
    [tex]=8/2,-4/2)[/tex]
    [tex]M(x,y)=(-4,-2)[/tex]

    Then I will find the radius:
    [tex]r^2=(x-h)^2+(y-k)^2[/tex]
    [tex]r^2=(0-4)^2+(0+2)^2[/tex]
    [tex]r^2=16+4[/tex]
    [tex]r^2=20[/tex]

    so
    [tex](x-4)^2+(y+2)^2=20[/tex]
     
    Last edited by a moderator: Jun 4, 2015
  2. jcsd
  3. Jun 4, 2015 #2

    Mark44

    Staff: Mentor

    That's what I get, as well.

    BTW, this looks like homework, or at least a problem from a textbook, so I'm moving it to the homework section.
     
  4. Jun 4, 2015 #3
    Thank you Mark,
    I wasn't sure if I should post under pre calculus as I couldn't find any geometry there, thanks again.
     
  5. Jun 4, 2015 #4

    Mark44

    Staff: Mentor

    This would come under the heading of analytic geometry, so the Precalc section is the right place for it.
     
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