Did I make a mistake in evaluating this integral?

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SUMMARY

The integral evaluation discussed is $$\int^4_0 \frac{6z + 5}{2z + 1} dz$$, which simplifies to $$\int^4_0 3 + \frac{2}{2z + 1} dz$$. The final result is correctly computed as $$[3z + 2\ln|2z + 1|]^4_0 = 12 + 2\ln|9|$$. However, a mistake was identified regarding the factor of 2 in front of $$\ln|2z + 1|$$, which cancels with the 2z in the denominator, affecting the evaluation.

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shamieh
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Can someone check my work?$$
\int^4_0 \frac{6z + 5}{2z + 1} dz$$

$$\int^4_0 3 + \frac{2}{2z + 1} dz$$
$$
[3z + 2\ln|2z + 1|]^4_0 = 12 + 2\ln|9| $$
 
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As far as I can see, you´ve done a great job - except for the factor 2 in front of ln|2z+1|
 
the 2 cancels out with the 2z doesn't it? i think i see where i made my mistake
 
shamieh said:
the 2 cancels out with the 2z doesn't it? i think i see where i made my mistake

$\displaystyle \begin{align*} \int{\frac{1}{a\,x + b} \, dx} = \frac{1}{a} \ln{ \left| a \, x + b \right| } + C \end{align*}$
 

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