Did I Misuse the Parallel Axis Theorem for Polar Moment of Inertia?

  • Thread starter Thread starter Usaid3112
  • Start date Start date
  • Tags Tags
    Statics
Click For Summary
SUMMARY

The discussion centers on the application of the Parallel Axis Theorem in calculating the Polar Moment of Inertia for a given shape. The correct answer for the Polar Moment of Inertia, as per the textbook, is J=330 cm4. The centroidal moment of inertia about the x-axis is confirmed to be IXC = 142.41 cm4, which is not the same as the moment of inertia about the x-axis as depicted in the figure. The discussion emphasizes that the Parallel Axis Theorem should not be applied when calculating IYC.

PREREQUISITES
  • Understanding of the Parallel Axis Theorem
  • Knowledge of centroidal moment of inertia
  • Familiarity with polar moment of inertia calculations
  • Basic principles of mechanics and structural analysis
NEXT STEPS
  • Study the derivation and applications of the Parallel Axis Theorem
  • Learn how to calculate centroidal moments of inertia for various shapes
  • Explore the differences between centroidal and non-centroidal moment of inertia
  • Investigate advanced topics in mechanics, such as composite shapes and their inertia properties
USEFUL FOR

Mechanical engineers, structural analysts, and students studying mechanics who are looking to deepen their understanding of moment of inertia calculations and the application of the Parallel Axis Theorem.

Usaid3112
Messages
2
Reaction score
0
Homework Statement
the centroidal moment of inertia about the x axis for the area shown is 142.41 cm^4. Most nearly what is the centroidal polar moment of inertia. The answer is C. What confuses me is that the solution says that the Y axis passes through the Centroid of the shape so parallel axis theorem shouldn't be applicable. Clarifications would be appreciated.
Relevant Equations
Iyc= Iy + Ad^2
IMG_0488.jpg
 

Attachments

  • IMG_0486.jpg
    IMG_0486.jpg
    45.2 KB · Views: 55
Physics news on Phys.org
The apparent correct answer given in the textbook is J=330 cm^4. I ended up using parallel axis theorem as I could not see how the Y axis passed through the centroid as the given y axis is completely towards the left side of the whole shape.My attempt at this question:-
 

Attachments

  • IMG_0489.jpeg
    IMG_0489.jpeg
    58.5 KB · Views: 58
Usaid3112 said:
The apparent correct answer given in the textbook is J=330 cm^4. I ended up using parallel axis theorem as I could not see how the Y axis passed through the centroid as the given y axis is completely towards the left side of the whole shape.My attempt at this question:-
The centroidal moment of inertia "about the x-axis" is given to be IXC = 142.41 cm4. You can check that this is the moment of inertia about an axis parallel to the x-axis that passes through the centroid. So, it is not the moment of inertia about the x-axis as drawn in the figure.

The same applies to IYC. So, you would not use the parallel axis theorem in calculating IYC.

1722446153230.png
 
  • Like
Likes   Reactions: SammyS and vela

Similar threads

  • · Replies 28 ·
Replies
28
Views
2K
Replies
2
Views
2K
Replies
11
Views
3K
Replies
25
Views
2K
  • · Replies 40 ·
2
Replies
40
Views
6K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K