- Homework Statement
- What is the mass moment of inertia (kg-m^2) of the following steel plate about the x-axis
- Relevant Equations
Mass moment of inertia of a quarter circular plate about its base is (1/4)mr^2
Mass moment of inertia of a rectangle along its base about the x-axis is(1/3)mh^2
thickness of the steel plate is 5mm
density of steel is 7850 kg/m^3
My thought process was to get the mass moment of inertia of the rectangle and then subtract the mass moment of inertia of the quartercircle from it.
The MMoI of the rectangle is:
(1/3)(0.005*7850*.6*.3)(.3^2)= 0.212 meters
The MMoI of the quartercircle is:
(1/4)(0.005*7850*¼π 0.3^2)(.3^2) + ?
My problem is that I'm not sure how to apply the parallel axis theorem to get the Mass moment of inertia of the quarter circle about the x-axis.