Did I Solve the RL Circuit Problem Correctly?

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Homework Help Overview

The discussion revolves around an RL circuit problem involving an emf of 10V, a resistor of 10 Ohms, and an inductor of 1.0 H. The original poster seeks to determine the current at a specific time after switching the circuit configuration and asks for validation of their calculations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the initial current using Ohm's Law and applies the discharge formula for the RL circuit. Participants question the choice of initial current and seek clarification on the calculations performed.

Discussion Status

Some participants provide feedback on the calculations, with one confirming the correctness of the answers. However, the discussion includes questions about the methodology and assumptions made in the problem-solving process.

Contextual Notes

The original poster's inquiry is framed within the constraints of a homework assignment, which may limit the depth of exploration regarding the underlying principles of RL circuits.

musiliu
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Homework Statement



An emf of 10V is connected to the RL circuit (R = 10 Ohms, L = 1.0 H)
shown below for long, long time (the switch is in position 1). Then, at t = 0
the switch is thrown into position 2. Find the current in the circuit at t = 0.2
s. When will the current drop to 0.001 A?
[PLAIN]http://img132.imageshack.us/img132/5139/physicsproblem.jpg

Homework Equations



"Discharge" of RL circuit: I(t) = I0e-Rt/L

The Attempt at a Solution



Part 1:
This looks like simple plug-in problem:
I0 = E / R after "long, long time"
E = 10 V, R = 10 Ohms, L = 1 Henry
I(0.2) = 0.135 A

Part 2:
I set I = .001 A and solved for t:
t = 0.691 s

Are my answers correct and did i do this problem correctly?
 
Last edited by a moderator:
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What did you use as Io, how did you do part 2?
 
I used Io equal to E / R, voltage over resistance from Ohm's Law, because for "long, long time", the initial current is equal to that...

so is my answer correct?
 
Your answers are correct. ehild
 

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