The current in a series RL circuit

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SUMMARY

The discussion focuses on calculating the resistance R in a series RL circuit where the inductance L is given as 2.0 mH and the current reaches 20% of its final value in 3.4 μs. The relevant equation used is I = I_0(1 - e^(-t/(L/R))). The participants confirm the validity of this equation for the problem at hand and seek clarification on determining the final current value and the current after 3.4 μs. The solution involves rearranging the equation to isolate R based on the provided parameters.

PREREQUISITES
  • Understanding of series RL circuit behavior
  • Familiarity with the exponential growth of current in inductive circuits
  • Knowledge of the mathematical constant e and its application in circuit equations
  • Ability to manipulate algebraic equations to solve for unknown variables
NEXT STEPS
  • Study the derivation of the RL circuit current equation I = I_0(1 - e^(-t/(L/R)))
  • Learn how to calculate time constants in RL circuits
  • Explore the impact of varying resistance on the time taken to reach a certain current level
  • Investigate practical applications of RL circuits in electronic devices
USEFUL FOR

Electrical engineering students, educators teaching circuit theory, and professionals working with inductive components in electronic design.

BryceHarper
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Homework Statement



The current in a series RL circuit increases to 20% of its final value in 3.4μs. If L = 2.0mH, what is the resistance R?

Homework Equations



I=I_0(1-e^(-t/(L/R))) <----Im not sure if this equation is right?


The Attempt at a Solution



I'm unsure how to start this problem, or if I'm on the right track with this equation?
 
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BryceHarper said:
The current in a series RL circuit increases to 20% of its final value in 3.4μs. If L = 2.0mH, what is the resistance R?
I=I_0(1-e^(-t/(L/R))) <----Im not sure if this equation is right?
Neither do I, but assuming it is...
In terms of the variables in that equation, what would be the final value, and what would be the value after 3.4μs?
 

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