Difference between Calculus 4th edition and Calculus 3rd edi

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SUMMARY

The primary difference between the 3rd and 4th editions of "Calculus" by Michael Spivak is the addition of a small amount of new material and more problem examples in the 4th edition. Users who already own the 3rd edition may not find the updates significant enough to warrant the purchase of the 4th edition, especially considering the higher cost. However, for those seeking additional problem-solving examples, the 4th edition is a better choice. Ultimately, both editions are highly regarded, and the decision may depend on budget constraints and the need for extra practice problems.

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  • Familiarity with calculus concepts and terminology
  • Understanding of mathematical problem-solving techniques
  • Access to either the 3rd or 4th edition of "Calculus" by Michael Spivak
  • Basic knowledge of academic publishing and editions
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  • Investigate online platforms for purchasing used academic books
  • Review user feedback on the effectiveness of different calculus editions
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Students of calculus, educators seeking effective teaching resources, and anyone considering purchasing a calculus textbook for enhanced problem-solving practice.

vish_maths
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Difference between Calculus 4th edition and Calculus 3rd edition by Michael Spivak?

I currently possesses Calculus 3rd edition by Michael Spivak in it's electronic form. However, I am considering buying a hard copy and have the option of buying either a used 3rd edition or a new 4th edition.

Since, the 4th edition is quite costly for me, I want to be absolutely sure before buying. I haven't been able to locate an electronic copy of the 4th edition anywhere.

So, would someone be kind enough to tell me precisely the differences between the two books.

I expect to solve a good amount of hard calculus problems so I would choose whichever has more problems.

Thank you for your help.
 
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Both are good books. If you can save lots of money by buying the third edition, then go for it.
 
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There is some information regarding that on the publisher'shttp://www.mathpop.com/mainhtms/bip.htm webpage:
This new edition adds only a small amount of material and some problems; it does not contain a significant amount of new material, and will probably not be of interest to those who already have the 3rd edition.
 
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They both are good books, but the fourth edition has more examples on problems and gives you the idea on how to solve problems
so new editions are good but don't lose the old editions
 
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Thank you everyone for your replies. i bought the 4th edition itself
 

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