Differential equation, Bernoulli's

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SUMMARY

The discussion focuses on solving a Bernoulli differential equation represented by the equation (2x²lny - x)y' = y. The user attempted to manipulate the equation by expressing it as y'/y = 1/(2x²lny - x) and considered substituting z = 1/y. However, they encountered difficulties due to the presence of the natural logarithm of y. A suggested approach is to substitute z = ln y and evaluate the derivative z' to simplify the problem.

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  • Knowledge of substitution methods in differential equations
  • Familiarity with derivatives and logarithmic functions
  • Basic algebraic manipulation skills
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Homework Statement



Hello everybody :) Now, I have a differential equation to solve. Its a Bernoulli's type of eq.


Homework Equations



(2x2lny-x)y' = y

The Attempt at a Solution



I tried of putting it in this way: y'/y = 1/2x2lny-x and then considerin z=1/y, but it doesn't seem to solve the problem, because the lny sort of gets in the way. Any help would be appreciated. Thanks :)
 
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Substitute z=\ln y into the equation. Hint: Evaluate the derivative z' first!
 
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The only thing I hadn't tried :D Thanks a lot :D
 

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