- #1
Mamdoh Abughalion
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Homework Statement
.[/B]Find dy/dx
Y^x = X^y
Homework Equations
F'( Ln(x)) = 1/x
Lnx^y = yLnx
The Attempt at a Solution
Ln(Y^x) = Ln(X^y)
X • Lny = Y • Lnx , should I differentiate now or :
Y = X • Lny/Lnx
Y = X • Logxy , then differentiate ?
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