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Differential equation in simple RC-circuit

  1. Mar 25, 2012 #1
    Hi guys,

    I know this should be obvious, but there's something I am just NOT getting.

    Imagine a simple series RC circuit with a DC source as shown in the attachment. As can be seen from the picture, I have solved the differential equation in capacitor current in the time domain. In order to be able to solve the problem, I have assumed that dE/dt = 0 as this is a dc source.

    What I wish to know is why can't I take the Laplace transform of both sides of the equation (*)? I know that L(0) = 0, so this would give a bogus equation (i.e. I(s) = 0, which is wrong). But if my equation (*) is right, then why can't I use the laplace transform of both sides at this point?

    From textbooks, I read that the DC source is considered as a step input, thus in the Laplace domain, this would be E/s. So again, what is wrong with equation (*)? And why do I get the right answer at the end?

    Again, as I said, I think this should be obvious, so please don't hesitate to point out trivialities.

    Thanks for your understanding.
    e.
     

    Attached Files:

    Last edited: Mar 25, 2012
  2. jcsd
  3. Mar 26, 2012 #2
    Laplace transform of your equation (*) should be
    [tex]sI+\frac{1}{RC}I=0[/tex]

    Solve for I and invert it. You should obtain the same answer.
     
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