Differential equation of a circle

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Discussion Overview

The discussion centers around the differential equation of a circle, specifically how the constant radius 'a' can be inferred from the differential equation representation. Participants explore the implications of the equation and its formulation, questioning the nature of 'a' as a constant versus a variable.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant presents the equation of a circle and its differential equation form, questioning how 'a' can be inferred as a constant from this representation.
  • Another participant suggests that the equation should include a plus sign instead of a minus sign, arguing that 'a' could potentially be a function of x and/or y.
  • A later reply emphasizes the relationship of the right-hand side of the equation to the local radius of curvature of a curve, prompting a question about the definition of curvature and radius of curvature.

Areas of Agreement / Disagreement

Participants express differing views on whether 'a' can be considered a constant based on the differential equation, indicating a lack of consensus on this point.

Contextual Notes

There are unresolved assumptions regarding the nature of 'a' and its dependence on the variables involved in the equation. The discussion also reflects uncertainty about the correct formulation of the differential equation.

iVenky
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Consider a circle of radius 'a' and centre (h,b)

then the equation of the circle is given by (x-h)2 + (y-b)2 = a2

I expressed this in terms of differential equations which is -


a= {[1+(dy/dx)2]3/2}/{d2y/dx2}
According to my book - this equation indicates that 'a' is a constant. How can you infer from this equation that 'a' is a constant? (Note: I know that 'a' is a constant but I can't understand how you can infer that from this differential equation).

Thanks in advance.
 
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One more doubt- I tried using Latex for representing that diff equation as one divided by the other but it seems to be working only for numbers and not for differentiation
 
iVenky said:
Consider a circle of radius 'a' and centre (h,b)

then the equation of the circle is given by (x-h)2 + (y-b)2 = a2

I expressed this in terms of differential equations which is -

a= {[1-(dy/dx)2]3/2}/{d2y/dx2}
According to my book - this equation indicates that 'a' is a constant. How can you infer from this equation that 'a' is a constant? (Note: I know that 'a' is a constant but I can't understand how you can infer that from this differential equation).
I think that should be +, not -.
The equation cannot imply that the radius, a, is a constant. In general, it could be a function of x and or y.
 
Ya it is +. You are sure that this equation can't imply that it is a constant only?
 
iVenky said:
Consider a circle of radius 'a' and centre (h,b)

then the equation of the circle is given by (x-h)2 + (y-b)2 = a2

I expressed this in terms of differential equations which is -


a= {[1+(dy/dx)2]3/2}/{d2y/dx2}
According to my book - this equation indicates that 'a' is a constant. How can you infer from this equation that 'a' is a constant? (Note: I know that 'a' is a constant but I can't understand how you can infer that from this differential equation).

Thanks in advance.

The right hand side of this equation is the relationship for the local radius of curvature of an arbitrary curve within the x-y plane. Do you know the definition of the curvature or its inverse, the radius of curvature?
 

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