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## Main Question or Discussion Point

I know this looks really easy, but trying to solve this is amazingly difficult. I couldnt do it, i kept getting wrong answers. Any body got any idea how to solve this?

- Thread starter false_alarm
- Start date

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I know this looks really easy, but trying to solve this is amazingly difficult. I couldnt do it, i kept getting wrong answers. Any body got any idea how to solve this?

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When methods have you leart because there is more then one way to solve the above equation.I know this looks really easy, but trying to solve this is amazingly difficult. I couldnt do it, i kept getting wrong answers. Any body got any idea how to solve this?

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If no one else helps you out I'll try to solve it with that method tomorrow. First though you have to show me the steps you tried.

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(1/2)x-1=g(x)

y'-y=g(x)....linear form

d(x)y'-s(x)y=(d(x)y)'.....product rule

only works if d(x)'=s(x)

the only function that is its own integral, that i could think of, is e[tex]^{x}[/tex]

but since the y is negative, it would have to be e[tex]^{-x}[/tex]

so then u could say,

e[tex]^{-x}[/tex]y'-e[tex]^{-x}[/tex]y=e[tex]^{-x}[/tex]g(x)

(e[tex]^{-x}[/tex]y)'=e[tex]^{-x}[/tex]g(x)....use the product rule

e[tex]^{-x}[/tex]y=antiderivative(e[tex]^{-x}[/tex]g(x))........took antiderivative

y=antiderivative(e[tex]^{-x}[/tex]((1/2)x-1))/e[tex]^{-x}[/tex].......divide both sides by e[tex]^{-x}[/tex]

I think im screwing up in the simplifying part. But, the integration becomes tricky

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y=(-1/2)x+(1/2)

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