Differential Equations? Fill in the table.

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SUMMARY

The discussion revolves around solving the differential equation dy/dt = 0.2y with an initial value of y = 6. The correct approach involves using Euler's approximation method rather than directly applying the exact solution y = 6e^(0.2t). The values calculated using Euler's method yield y values of 6 at t=0, 7.2 at t=1, 8.64 at t=2, 10.368 at t=3, and 12.4416 at t=4, which are confirmed as accurate.

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ani9890
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Fill in the missing values in the table given if you know that dy/dt=0.2y. Assume the rate of growth given by dy/dt is approximately constant over each unit time interval and that the initial value of y is 6.

Table:
t-0-1-2-3-4
y-6-?-?-?-?
(fill in the missing values where there is a question mark)

I got:
t = 1, y = 7.33
At t = 2 , y = 8.95
At t = 3 , y =10.93
At t = 4 , y = 13.35
using y=6e^(.2t)

but it is wrong, Help?
 
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ani9890 said:
Fill in the missing values in the table given if you know that dy/dt=0.2y. Assume the rate of growth given by dy/dt is approximately constant over each unit time interval and that the initial value of y is 6.

Table:
t-0-1-2-3-4
y-6-?-?-?-?
(fill in the missing values where there is a question mark)

I got:
t = 1, y = 7.33
At t = 2 , y = 8.95
At t = 3 , y =10.93
At t = 4 , y = 13.35
using y=6e^(.2t)

but it is wrong, Help?

You have apparently just plugged the t values into the exact solution. But that is not what the problem asks you to do. What you are asked to do looks a lot like Euler's approximation method. So start with knowing at t=0 the slope is ##.2(6)##, assume that constant slope to get the value at ##t=1##. Then do the same thing for the next steps.
 
Thank you, I redid the problem using y₂ = y₁ + m(x₂ - x₁) and got:

t --- y
0 .. 6
1 .. 7.2
2 .. 8.64
3 .. 10.368
4 .. 12.4416

can you please check if this is correct?
Thank you
 

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