Differentiate y=2t+3 and x=t^2 -t

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SUMMARY

The discussion focuses on differentiating the functions y=2t+3 and x=t^2-t with respect to the variable t. The correct derivatives are identified as dy/dt=2 and dx/dt=2t-1. To find dy/dx, the relationship dy/dx = (dy/dt)/(dx/dt) is established, leading to the conclusion that dy/dx = 2/(2t-1). The participants clarify the need to express answers in factored form when applicable.

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Homework Statement


Differentiate each function and if possible express your answer in factoring form
y=2t+3 and x=t^2 -t

Homework Equations





The Attempt at a Solution


im really lost on this question but this is what i did so far
x=t(t-1)
x/t-1=t
so: y=2(x/t-1)+3
but now I am lost because that seems wrong you can't have two variables right??
 
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Instead of factoring it first, just differentiate them both with respect to t.

y=2t+3 and x=t^2 -t


Remember your rules of differentiation? If y=xn then dy/dx =nxn-1.
 
oh ok so:
dy/dx=2
dy/dx=2t-1
but then what...
 
jay17jay said:
oh ok so:
dy/dx=2
dy/dx=2t-1
but then what...

I think you mean dy/dt=2, and dx/dt=2t-1. And what does it mean to "express your answer in factoring form"?
 
sorry yes in respect to t.
the questions just states when possible express you answer in factored form.
 
jay17jay said:
sorry yes in respect to t.
the questions just states when possible express you answer in factored form.

Then I believe you're done. Unless you're also expected to find dy/dx.
 
yes i think am suppose to do that and that's where I am confused how do i combine them?
the question says "if y=2t+3 and x+t^2 -t, find dy/dx"
 
dy/dx = (dy/dt)/(dx/dt), if I recall correctly.
 
perfect thankyou :)
 
  • #10
Char. Limit said:
dy/dx = (dy/dt)/(dx/dt), if I recall correctly.

Your recollection is correct. If y is a function of x, and x is a function of t, then dy/dt = dy/dx * dx/dt.

Solve this equation for dy/dx to get dy/dx = (dy/dt)/(dx/dt).
 

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