Differentiation of an exponential function

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Homework Help Overview

The discussion revolves around finding the coordinates of a point on the curve defined by the function y = e^x where the gradient is equal to 2. The problem involves differentiation, particularly with respect to exponential functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need for differentiation and question the derivative of the exponential function. Some suggest using the properties of natural logarithms and the chain rule to find the derivative, while others emphasize the simplicity of differentiating e^x directly.

Discussion Status

There are multiple lines of reasoning being explored, with some participants offering guidance on differentiation techniques. However, there is no explicit consensus on the next steps, as some participants express uncertainty about how to proceed with the problem.

Contextual Notes

Participants note that the derivative represents the gradient, and there is a focus on solving the equation dy/dx = 2 to find the x-coordinate. The discussion reflects a mix of confidence and confusion regarding the differentiation process.

pavadrin
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Hey,
I have a problem involving natural logs which has got me confused, even though it appears simple.
The problem: Find the exact coordinates of the point on [tex]y = e^x[/tex] where the gradient is 2.
From previous experience, I know that differentiation is required, but because of the e I am not sure on how to go about this. After the differentiation I think I can manage to complete it.
Thanks,
Pavdarin
 
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pavadrin said:
Hey,
I have a problem involving natural logs which has got me confused, even though it appears simple.
The problem: Find the exact coordinates of the point on [tex]y = e^x[/tex] where the gradient is 2.
From previous experience, I know that differentiation is required, but because of the e I am not sure on how to go about this. After the differentiation I think I can manage to complete it.
Thanks,
Pavdarin

Well what is the derivative of [tex]y = e^x[/tex]?
 
if you don't know it you can find out using the given that d/dx ln x = 1/x and then calculate d/dx ln [tex]e^x[/tex] using the chain rule
 
If you know how to do this kind of problem then all you need is the derivative of e^x which is just e^x. Just do this problem as you would do if "y" was any other function, for example a polynomial.
 
thanks for the help, however i am still unsure on how to approach this problem
 
pavadrin said:
thanks for the help, however i am still unsure on how to approach this problem

the derivative is the gradient, so the following must be solved:

[tex]\frac {dy} {dx}\ = 2[/tex]

This will give you the x-coordinate.
 
Last edited:
pavadrin said:
thanks for the help, however i am still unsure on how to approach this problem

You "approach" this problem by differentiating ex! What is the derivative of ex? (It's the world's easiest derivative!)
 

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