Difficult polynomial question involving factor and remainder theorems

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SUMMARY

The discussion centers on proving that \( (a-b) \) is a factor of \( a^5-b^5 \) using the Remainder and Factor Theorems. The participant initially struggles with polynomial division but is guided to recognize that \( a^5-b^5 \) can be expressed as \( (a-b)(a^4 + a^3b + a^2b^2 + ab^3 + b^4) \). The other factor, \( a^4 + a^3b + a^2b^2 + ab^3 + b^4 \), is derived through polynomial long division or by recognizing the pattern in the difference of powers.

PREREQUISITES
  • Understanding of polynomial functions and their properties
  • Familiarity with the Remainder Theorem
  • Knowledge of the Factor Theorem
  • Ability to perform polynomial long division
NEXT STEPS
  • Study polynomial long division techniques in detail
  • Explore the application of the Remainder Theorem in various polynomial problems
  • Practice factoring higher-degree polynomials using the Factor Theorem
  • Review examples of the difference of powers and their factorizations
USEFUL FOR

Students studying algebra, particularly those focusing on polynomial functions, educators teaching polynomial factorization, and anyone preparing for exams involving algebraic expressions and theorems.

stfz
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Homework Statement



Prove that ##(a-b)## is a factor of ##a^5-b^5##, and find the other factor.

Homework Equations



Remainder theorem : remainder polynomial ##p(x)## divided by ##(x-a)## is equal to ##p(a)##
Factor theorem : if remainder = 0, then divisor was a factor of dividend.

The Attempt at a Solution



I think am able to prove that it is a factor:

##P(x) = x^5 - b^5##; we replace a with x
##P(x) = (x-b)Q(x) + 0## ; we assume that (x-b) is a factor
##P(b) = (b-b)Q(x) + 0 = 0 ##; proves that .. um.. I think I'm going the wrong way anyway. This doesn't really prove anything? er.. eh.. ?

And I can't really find the other factor
I could do most of the other questions in the exercise, but not this one (and other related ones!)

Any help would be appreciated
 
Last edited:
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stfz said:

Homework Statement



Prove that ##(a-b)## is a factor of ##a^5-b^5##, and find the other factor.

Homework Equations



Remainder theorem : remainder polynomial ##p(x)## divided by ##(x-a)## is equal to ##p(a)##
Factor theorem : if remainder = 0, then divisor was a factor of dividend.

The Attempt at a Solution



I think am able to prove that it is a factor:

##P(x) = x^5 - b^5##; we replace a with x
##P(x) = (x-b)Q(x) + 0## ; we assume that (x-b) is a factor
##P(b) = (b-b)Q(x) + 0 = 0 ##; proves that .. um.. I think I'm going the wrong way anyway. This doesn't really prove anything? er.. eh.. ?

And I can't really find the other factor
I could do most of the other questions in the exercise, but not this one (and other related ones!)

Any help would be appreciated
Do you know long division with polynomials, or synthetic division ?
 
Last edited:
Yes. However, attempting polynomial division on (x^5+b^5) didn't quite work for me. If that's how to solve the question, could someone give me an example?
 
stfz said:
Yes. However, attempting polynomial division on (x^5+b^5) didn't quite work for me. If that's how to solve the question, could someone give me an example?

Maybe that's because you want to divide (a^{5}-b^{5}) by (a - b).

Start off with a few warm-up exercises:

(a^{2}-b^{2})/(a-b)

(a^{3}-b^{3})/(a-b)

You should know the answer to the first exercise by inspection.
 
Woops, got what I missed. Thanks!
 

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