Difficult version of boatman problem

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Estudiante Curioso
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1. Problem
A boatman crosses a river of width ##D## from a point ##O##, looking to get to point ##A## on the opposite riverbank. Suppose that the flowrate is uniform with velocity of magnitude ##v_0##. The boat has a velocity ##\vec{v_1}## relative to the water, with constant magnitude, and it always points towards the point ##A##. Calculate the time that the boatman takes to ge t to point ##A##.

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We were also hinted that it may be useful to state that ##\vec{r_A}-\vec{r_B}=\alpha(t)\vec{v_1}## (because ##\vec{v_1}## points to ##A##), and then derive that expression.

2.The attempt at a solution
First I noticed that since ##||\vec{v_1}||## is constant, its derivative must be perpendicular to it. So the plan was to project ##\vec{v_b}## (obtained from the previous derivative) over the unitary vectors ##\hat{\vec{v_1}}## and ##\hat{\dot{\vec{v_1}}}## and then I would get two expressions from the previous derivative, from where I could potentially obtain ##\alpha(t)## through integration or a differential equation. I also noted that those unitary vectors define polar coordinates with respect to ##A##.

I arrived to the expressions $$v_1+\vec{v_0} \hat{v_1} = \alpha'(t) v_1$$ and $$v_0 \hat{\dot{\vec{v_1}}}= \alpha(t) ||\dot{\vec{v_1}}||$$
where I could use trigonometry to replace the dot products on the left with ##sin(\theta)## and ##cos(\theta)## (where ##\theta## is the angle between ##\vec{v_0}## and ##\vec{v_1}##), but I am completely puzzled as what to do with ##||\dot{\vec{v_1}}||## and if this method actually works.
 

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I do believe this problem has the same mathematical solution as one in which point ## A ## moves with a constant velocity upward, and the water has no flow of current. This same problem was given by @micromass in problem 4 of his October 2016 challenge. https://www.physicsforums.com/threads/micromass-big-october-challenge.887447/ Note: You subtract ## y=v_o t ## from the y coordinate of the solution of the challenge problem. The problem gets solved, (I solved it), around posts 61-68 of the discussion. @Chestermiller also supplied portions of the solution.## \\ ## Hopefully, I'm not breaking the Physics Forums rules by supplying the solution. This is really a non-trivial problem, and in general, neither the student or the homework helper would be expected to solve this problem routinely.
 
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Thank you for your reply. I'm looking at the solution of the problem you posted, but I'm having a hard time understanding it. I'll keep trying.
Edit: I hadn't seen posts after 60, now it's much more clear.
 
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